Optimal. Leaf size=198 \[ \frac{\sqrt{d} \left (-a^2 d^2+10 a b c d+15 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 b^{3/2}}-\frac{c^{3/2} (5 a d+b c) \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{\sqrt{a}}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}+\frac{d \sqrt{a+b x} \sqrt{c+d x} (a d+11 b c)}{4 b} \]
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Rubi [A] time = 0.196168, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {97, 154, 157, 63, 217, 206, 93, 208} \[ \frac{\sqrt{d} \left (-a^2 d^2+10 a b c d+15 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 b^{3/2}}-\frac{c^{3/2} (5 a d+b c) \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{\sqrt{a}}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}+\frac{d \sqrt{a+b x} \sqrt{c+d x} (a d+11 b c)}{4 b} \]
Antiderivative was successfully verified.
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Rule 97
Rule 154
Rule 157
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x} (c+d x)^{5/2}}{x^2} \, dx &=-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\int \frac{(c+d x)^{3/2} \left (\frac{1}{2} (b c+5 a d)+3 b d x\right )}{x \sqrt{a+b x}} \, dx\\ &=\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\frac{\int \frac{\sqrt{c+d x} \left (b c (b c+5 a d)+\frac{1}{2} b d (11 b c+a d) x\right )}{x \sqrt{a+b x}} \, dx}{2 b}\\ &=\frac{d (11 b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{4 b}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\frac{\int \frac{b^2 c^2 (b c+5 a d)+\frac{1}{4} b d \left (15 b^2 c^2+10 a b c d-a^2 d^2\right ) x}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{2 b^2}\\ &=\frac{d (11 b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{4 b}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\frac{1}{2} \left (c^2 (b c+5 a d)\right ) \int \frac{1}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx+\frac{\left (d \left (15 b^2 c^2+10 a b c d-a^2 d^2\right )\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{8 b}\\ &=\frac{d (11 b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{4 b}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}+\left (c^2 (b c+5 a d)\right ) \operatorname{Subst}\left (\int \frac{1}{-a+c x^2} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )+\frac{\left (d \left (15 b^2 c^2+10 a b c d-a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{4 b^2}\\ &=\frac{d (11 b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{4 b}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}-\frac{c^{3/2} (b c+5 a d) \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{\sqrt{a}}+\frac{\left (d \left (15 b^2 c^2+10 a b c d-a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{4 b^2}\\ &=\frac{d (11 b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{4 b}+\frac{3}{2} d \sqrt{a+b x} (c+d x)^{3/2}-\frac{\sqrt{a+b x} (c+d x)^{5/2}}{x}-\frac{c^{3/2} (b c+5 a d) \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{\sqrt{a}}+\frac{\sqrt{d} \left (15 b^2 c^2+10 a b c d-a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 b^{3/2}}\\ \end{align*}
Mathematica [A] time = 1.14313, size = 208, normalized size = 1.05 \[ \frac{\frac{\sqrt{d} \sqrt{c+d x} \left (-a^2 d^2+10 a b c d+15 b^2 c^2\right ) \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )}{\sqrt{b c-a d} \sqrt{\frac{b (c+d x)}{b c-a d}}}+\frac{\sqrt{a+b x} \sqrt{c+d x} \left (a d^2 x+b \left (-4 c^2+9 c d x+2 d^2 x^2\right )\right )}{x}-\frac{4 b c^{3/2} (5 a d+b c) \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{\sqrt{a}}}{4 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.015, size = 503, normalized size = 2.5 \begin{align*} -{\frac{1}{8\,bx}\sqrt{bx+a}\sqrt{dx+c} \left ( \ln \left ({\frac{1}{2} \left ( 2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc \right ){\frac{1}{\sqrt{bd}}}} \right ) x{a}^{2}{d}^{3}\sqrt{ac}-10\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) xabc{d}^{2}\sqrt{ac}-15\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) x{b}^{2}{c}^{2}d\sqrt{ac}+20\,\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{d{x}^{2}b+adx+bcx+ac}+2\,ac}{x}} \right ) xab{c}^{2}d\sqrt{bd}+4\,\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{d{x}^{2}b+adx+bcx+ac}+2\,ac}{x}} \right ) x{b}^{2}{c}^{3}\sqrt{bd}-4\,{x}^{2}b{d}^{2}\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}-2\,xa{d}^{2}\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}-18\,xbcd\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}+8\,b{c}^{2}\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac} \right ){\frac{1}{\sqrt{d{x}^{2}b+adx+bcx+ac}}}{\frac{1}{\sqrt{bd}}}{\frac{1}{\sqrt{ac}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 25.6722, size = 2414, normalized size = 12.19 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{a + b x} \left (c + d x\right )^{\frac{5}{2}}}{x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.66599, size = 806, normalized size = 4.07 \begin{align*} \frac{2 \, \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d} \sqrt{b x + a}{\left (\frac{2 \,{\left (b x + a\right )} d^{2}{\left | b \right |}}{b^{2}} + \frac{9 \, b^{3} c d^{3}{\left | b \right |} - a b^{2} d^{4}{\left | b \right |}}{b^{4} d^{2}}\right )} - \frac{8 \,{\left (\sqrt{b d} b^{2} c^{3}{\left | b \right |} + 5 \, \sqrt{b d} a b c^{2} d{\left | b \right |}\right )} \arctan \left (-\frac{b^{2} c + a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}}{2 \, \sqrt{-a b c d} b}\right )}{\sqrt{-a b c d} b} - \frac{16 \,{\left (\sqrt{b d} b^{4} c^{4}{\left | b \right |} - 2 \, \sqrt{b d} a b^{3} c^{3} d{\left | b \right |} + \sqrt{b d} a^{2} b^{2} c^{2} d^{2}{\left | b \right |} - \sqrt{b d}{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2} b^{2} c^{3}{\left | b \right |} - \sqrt{b d}{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2} a b c^{2} d{\left | b \right |}\right )}}{b^{4} c^{2} - 2 \, a b^{3} c d + a^{2} b^{2} d^{2} - 2 \,{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2} b^{2} c - 2 \,{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2} a b d +{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{4}} - \frac{{\left (15 \, \sqrt{b d} b^{2} c^{2}{\left | b \right |} + 10 \, \sqrt{b d} a b c d{\left | b \right |} - \sqrt{b d} a^{2} d^{2}{\left | b \right |}\right )} \log \left ({\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}{b^{2}}}{8 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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